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Welcome to Ofpad Wes. Hope you find the course useful. The forum is always available here for you to ask any and all questions.
Welcome to the community Zikra
Hi Frank,
It is unclear what you are having trouble with.
Can you help me understand the problem you are having trouble with? I will help you out.
Abhishek
Hi Gaberila.
Don’t apply the DS method on the division 8/7 = 5.
Instead move the denominator to the right of the equation:
8/7 = 5
8 = 5 x 7
8 = 35
8 = 3+5
8 = 8
Hope this helps and answers your question.
Hi Rain. So happy to see you embark on this journey.
Some of the methods are similar to Vedic math but the vedic math methodology has some additional methods that help you do speed math on paper.
Welcome to Ofpad Pihu
Hi Salvador
For 10 just keep the digit difference as -1 and the technique should still work.
Example for Addition
16 + 10 = 26
Digit difference of 16 = 5
Digit difference of 10 = -1
5 – 1 = 4
Digit difference of 26 = 4
Example for Subtraction
16 – 10 = 6
Digit difference of 16 = 5
Digit difference of 10 = -1
5 – (-1) = 6
Digit difference of 6 = 6
Example for Multiplication
16 x 10 = 160
Digit difference of 16 = 5
Digit difference of 10 = -1
5 x (-1) = -5
Digit difference of 160 = 1 – 6 = -5
Hope this answers your question
Hi Ken,
If you have the book, the practice exercises are at the end of each chapter.
Are you referring to something else?
Hi Jason,
The UT method can be used only for a 2 digit multiplier. The practice questions 13 to 18 will be updated in the next edition.
In the Vitruvian Method you would first do 667 x 386 and then 671 x 386. You should then combine the results together.
Let me know if this clarifies.
Welcome to the forum Riko.
Hi Stephen,
Where you draw the line will depend on the number of digits in the flag. If the flag has one digit, then you will draw the decimal line after one digit from the right.
In your example 1 is the pole and 3 is the flag. The flag is a one digit number which is 3. So you will draw the line between 2 and 4 in 64924 (i.e 6492|4).
If you divide 64924 by 224 then where you draw the line will depend on how you create the flag and the pole.
If in 224 you make 22 the pole and 4 the flag, then you will draw the line between 2 and 4 in 64924 (i.e 6492|4) because the flag 4 is only one digit.
If in 224 you make 2 the pole and 24 the flag, then you will draw the line between 9 and 2 in 64924 (i.e 649|24) because the flag 24 is two digits.
Hope this clarifies.
Here are the steps
125 x 8 = _ _ _ _
Multiplying Left to Right one digit at a time
We multiply 1 x 8 to get 8 which becomes the first digit of the answer.
125 x 8 = 8 _ _ _
We multiply 2 x 8 to get 16. We carry over the 1 in 16 so 8 becomes 9.
125 x 8 = 9 _ _ _
The second digit of 6 becomes the next digit of the answer.
125 x 8 = 9 6 _ _
We multiply 5 x 8 to get 40. We carry over the 4 in 40 so 96 becomes 100.
125 x 8 = 1 0 0 _
The 0 in 40 becomes the next digit of the answer.
125 x 8 = 1 0 0 0
1000 is the final answer.
Hi Akiva,
The denominator in your code does not include cases where the DS method correctly predicts a calculation as incorrect.
I have updated your code to reflect this and you can find the notebook here: https://github.com/abhivr/public_repo/blob/main/Digit_Sum_Checker.ipynb
When I wrote the book & created the course, I estimated the accuracy of the DS method using simple probability.
The digit sum can only be a number between 1 to 9. So there are 9 possible values.
8 of these 9 possible DS values will help you catch an error in the calculation without an issue.
One out of these 9 possible values is the DS of the correct answer but it can also be the DS of the incorrect answer.
So there are actually a total of 10 possible values for the Digit sum (9 Correct DS + 1 Incorrect DS) with one number repeating in Correct DS and Incorrect DS.
So 9 / 10 (90%) the DS method correctly predicts the calculation as incorrect & correct. But 1/10 times the DS method predicts the calculation is correct when it is actually incorrect.
Hope this clarifies.
Hi Pradnesh,
You can use the Math Palace technique. It is still a work in progress. You can get a free review copy for leaving an review on Amazon.
Here is the link: https://ofpad.com/math-palace
Abhishek
Here are the steps:
We are trying to multiply
= 67 x 8.
We break down 67 into (70 – 3). So we get:
= (70 – 3) x 8
Multiplying the individual numbers we have.
= 560 – 24
LR Subtraction without Round Up.
Here we subtract left to right.
560 – 24 = _ _ _
First number is 5 so it becomes the first digit of the answer.
560 – 24 = 5 _ _
Second digits is 6 – 2 = 4 it becomes the second digit of the answer.
560 – 24 = 5 4 _
We cannot subtract 0 – 4 so we must borrow 1 from the existing answer 54 so it becomes 53.
560 – 24 = 53 _
Now we subtract 10 – 4 to get 6 which is the last digit of the answer.
560 – 24 = 536.
Alternative LR Subtraction with Round Up.
If you want to do the LR Subtraction with round up, then here are the steps. To recap we are trying to subtract
560 – 24 = _ _ _
We can round up 24 to 30 so the equation becomes:
560 – (30 – 6) = _ _ _
530 – 30 + 6 = _ _ _
We subtract 560 – 30 to get 530
560 – 30 = 530.
We add the amount we rounded up which is 6 to get 536.
530 + 6 = 536.
536 is the final answer for 67 x 8.
Hope this clarifies.