Abhishek R

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  • in reply to: Worksheet multiplication #46708
    Abhishek R
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    Hi Frank,

    It is unclear what you are having trouble with.

    Can you help me understand the problem you are having trouble with? I will help you out.

    Abhishek

     

    in reply to: DS method check on page 17 of the book #46439
    Abhishek R
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    Hi Gaberila.

    Don’t apply the DS method on the division 8/7 = 5.

    Instead move the denominator to the right of the equation:

    8/7 = 5

    8 = 5 x 7

    8 = 35

    8 = 3+5

    8 = 8

    Hope this helps and answers your question.

    in reply to: Hello, Rain here! #45751
    Abhishek R
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    Hi Rain. So happy to see you embark on this journey.

    Some of the methods are similar to Vedic math but the vedic math methodology has some additional methods that help you do speed math on paper.

    in reply to: Hello I’m Pihu #45729
    Abhishek R
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    Welcome to Ofpad Pihu

    in reply to: DD Method #45309
    Abhishek R
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    Hi Salvador

    For 10 just keep the digit difference as -1 and the technique should still work. 

    Example for Addition

    16 + 10 = 26

    Digit difference of 16 = 5

    Digit difference of 10 = -1

    5 – 1 = 4

    Digit difference of 26 = 4

    Example for Subtraction 

    16 – 10 = 6

    Digit difference of 16 = 5

    Digit difference of 10 = -1

    5 – (-1) = 6

    Digit difference of 6 = 6

    Example for Multiplication 

    16 x 10 = 160

    Digit difference of 16 = 5

    Digit difference of 10 = -1

    5 x (-1) = -5

    Digit difference of 160 = 1 – 6 = -5

     

    Hope this answers your question

    in reply to: Practice exercises #41743
    Abhishek R
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    Hi Ken,

    If you have the book, the practice exercises are at the end of each chapter.

     

    Are you referring to something else?

     

    Abhishek R
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    Hi Jason,

    The UT method can be used only for a 2 digit multiplier. The practice questions 13 to 18 will be updated in the next edition.

    In the Vitruvian Method you would first do 667 x 386 and then 671 x 386. You should then combine the results together.

    Let me know if this clarifies.

    in reply to: Goddag all of you. ???? #39784
    Abhishek R
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    Welcome to the forum Riko.

    in reply to: Flag Pole Method’s Decimal Line #28957
    Abhishek R
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    Hi Stephen,

    Where you draw the line will depend on the number of digits in the flag. If the flag has one digit, then you will draw the decimal line after one digit from the right.

    In your example 1 is the pole and 3 is the flag. The flag is a one digit number which is 3. So you will draw the line between 2 and 4 in 64924 (i.e 6492|4).

    If you divide 64924 by 224 then where you draw the line will depend on how you create the flag and the pole.

    If in 224 you make 22 the pole and 4 the flag, then you will draw the line between 2 and 4 in 64924 (i.e 6492|4) because the flag 4 is only one digit.

    If in 224 you make 2 the pole and 24 the flag, then you will draw the line between 9 and 2 in 64924 (i.e 649|24) because the flag 24 is two digits.

    Hope this clarifies.

     

     

    in reply to: LR question #27880
    Abhishek R
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    Here are the steps

    125 x 8 = _ _ _ _

    Multiplying Left to Right one digit at a time

    We multiply 1 x 8 to get 8 which becomes the first digit of the answer.

    125 x 8 = 8 _ _ _

    We multiply 2 x 8 to get 16. We carry over the 1 in 16 so 8 becomes 9.

    125 x 8 = 9 _ _ _

    The second digit of 6 becomes the next digit of the answer.

    125 x 8 = 9 6 _ _

    We multiply 5 x 8 to get 40. We carry over the 4 in 40 so 96 becomes 100.

    125 x 8 = 1 0 0 _

    The 0 in 40 becomes the next digit of the answer.

    125 x 8 = 1 0 0 0

    1000 is the final answer.

     

    in reply to: Digit Sum Simulation #27739
    Abhishek R
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    Hi Akiva,

    The denominator in your code does not include cases where the DS method correctly predicts a calculation as incorrect.

    I have updated your code to reflect this and you can find the notebook here: https://github.com/abhivr/public_repo/blob/main/Digit_Sum_Checker.ipynb

    When I wrote the book & created the course, I estimated the accuracy of the DS method using simple probability.

    The digit sum can only be a number between 1 to 9. So there are 9 possible values.

    8 of these 9 possible DS values will help you catch an error in the calculation without an issue.

    One out of these 9 possible values is the DS of the correct answer but it can also be the DS of the incorrect answer.

    So there are actually a total of 10 possible values for the Digit sum (9 Correct DS + 1 Incorrect DS) with one number repeating in Correct DS and Incorrect DS.

    So 9 / 10 (90%) the DS method correctly predicts the calculation as incorrect & correct. But 1/10 times the DS method predicts the calculation is correct when it is actually incorrect.

    Hope this clarifies.

    in reply to: How to visualize numbers for Bridge Multiplication #27571
    Abhishek R
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    Hi Pradnesh,

    You can use the Math Palace technique. It is still a work in progress. You can get a free review copy for leaving an review on Amazon.

    Here is the link: https://ofpad.com/math-palace

    Abhishek

     

    in reply to: Multiplication after Rounding up and subtraction #27452
    Abhishek R
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    Here are the steps:

    We are trying to multiply

    = 67 x 8.

    We break down 67 into (70 – 3). So we get:

    = (70 – 3) x 8

    Multiplying the individual numbers we have.

    = 560 – 24

    LR Subtraction without Round Up. 

    Here we subtract left to right.

    560 – 24 = _ _ _

    First number is 5 so it becomes the first digit of the answer.

    560 – 24 = 5 _ _

    Second digits is 6 – 2 = 4 it becomes the second digit of the answer.

    560 – 24 = 5 4 _

    We cannot subtract 0 – 4 so we must borrow 1 from the existing answer 54 so it becomes 53.

    560 – 24 = 53 _

    Now we subtract 10 – 4 to get 6 which is the last digit of the answer.

    560 – 24 = 536.

    Alternative LR Subtraction with Round Up. 

    If you want to do the LR Subtraction with round up, then here are the steps. To recap we are trying to subtract

    560 – 24 = _ _ _

    We can round up 24 to 30 so the equation becomes:

    560 – (30 – 6) = _ _ _

    530 – 30 + 6 = _ _ _

    We subtract 560 – 30 to get 530

    560 – 30 = 530.

    We add the amount we rounded up which is 6 to get 536.

    530 + 6 = 536.

    536 is the final answer for 67 x 8.

    Hope this clarifies.

     

    in reply to: 736+255 #26987
    Abhishek R
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    Hi

    You need to carry over the 1 in 11 in your answer.

    Here are the steps:

    736 + 255 = _ _ _

    Adding 7 +2 we get 9. So 9 becomes the first digit of the answer.

    736 + 255 = 9  _ _

    Adding 3 +5 we get 8. And 8 becomes the first digit of the answer.

    736 + 255 = 9 8  _

    Adding 6 +5 we get 11. Since 11 has two digits, we carry over the first 1 in 11. So the answer 98 becomes 99.

    736 + 255 = 9 9  _

    The second 1 in 11 becomes the third digit of the answer.

    736 + 255 = 9 9  1

    Hope this clarifies.

    in reply to: DD Method #26476
    Abhishek R
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    You must alternate between odd and even.

    For example let’s take

    9876.1234

    Odd is marked as O.

    Even is marked as E.

    9 8 7 6 . 1 2 3 4

    E O E O . E O E O

    You start alternating from the left of the decimal place which is odd.

    Hope this clarifies

     

     

     

     

     

     

     

     

     

     

     

Viewing 15 posts - 1 through 15 (of 73 total)