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liked the video on the 11 times table but how does that work on a 2 digit multicant?
Hi Diego,
Here is an example 98 x 11
First digit becomes the first number of the answer.
So 9 in becomes the first digit of the answer98 x 11 = 9 _ _
Sum of the two digits becomes the next digit digit of the answer.
So the sum of the two digits of 98 is 9+8 = 17.Since there are two digits in 17 we carry over the 1 in 17. So adding 1 from 17 to first calculated digit 9 we get 9+1 =10
98 x 11 = 10 _ _
The 7 of 17 becomes the next digit of the answer.
98 x 11 = 107 _
The last digit becomes the last number of the answer.
So 8 which is the last digit becomes the last number of the answer.
98 x 11 = 1078Let me know if this helped.
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